Ethanol Rocket

Theory

Ethanol 3d model

• 

  The Ethanol

• 

  C2H6O

• 

  The Ethanol

Atom positions

-1.1712	0.2997	0.0000	O
-0.0463	-0.5665	0.0000	C
1.2175	0.2668	0.0000	C
-0.0958	-1.2120	0.8819	H
-0.0952	-1.1938	-0.8946	H
2.1050	-0.3720	-0.0177	H
1.2426	0.9307	-0.8704	H
1.2616	0.9052	0.8886	H
-1.1291	0.8364	0.8099	H

HCH bonds are assumed to be undistorded tetraherdal angle 109.5 degrees. Actually the electrons repeal each other. The HOC bond is 104.5 deg because. . .

Valence shell electron-pair repulsion theory (VSEPR theory). . .

Van der Waals radius

Atom	Radius	Relative radius
C	170 pm	1.42
H	120 pm	1.00
O	152 pm	1.27

Use CPK coloring convention, white (hydrogen), black (carbon) and red (oxygen).

Ethanol reaction with Oxygen and Air

Ethanol reaction with oxygen

${\textrm {C}}_{2}{\textrm {H}}_{6}{\textrm {O}}+3{\textrm {O}}_{2}\to 2{\textrm {CO}}_{2}+3{\textrm {H}}_{2}{\textrm {O}}$

The molecular weight of ethanol is $46.069$ g/mol, and the molar weight of oxygen is 32 g/mol. The oxygen--ethanol fuel ratio is $3\times 32/46=2.1$. We need $2.1$ kg of oxygen to $1$ kg of ethanol. The air consists of 23.2 mass-% of oxygen, thus the air--ethanol ratio is $2.1/0.232=9$.

The volume-% of oxygen in air is 20.9%. The volume of the bottle is $V=500$ ml which gives the amount of oxygen to be $0.209V=0.209\times 500=104.5$ ml $=0.1045\times 1.314=0.137$ g of oxygen, which gives the amount of ethanol $0.137/2.1=0.0659$ g $=0.0659/0.789=0.0834$ ml. OR directly using air--ethanol ratio we have $\rho V/9=1.2041\times 0.5/9=0.066$ gram. That amount equals to $V/\rho _{\textrm {Ethanol}}=0.066g/(789g/l)=0.084$ ml $=84$mm³. Almost the same result using the methods. See the attached spreadsheet for detailed calculations.

The energy released by burning ethanol is 17.9 kJ/ml. Thus, $0.084$ ml of ethanol releases $1,50$ kJ of energy. This energy is converted into heat, sound and projectile motion (plus others).

Densities

	Density $\rho$	At
Oxygen (g)	1.429 g/l	STP
Oxygen (g)	1.314 g/l	20 °C
Ethanol (l)	789.45 g/l	20 °C
Air (l)	1.2041 g/l	20 °C

File:Ethanol oxygen combustion.ods

The inner diameter of the rocket bottle is 25 mm. The height of the ethanol in the cap need to be $V=\pi r^{2}h\iff h={\frac {V}{\pi r^{2}}}={\frac {84mm^{3}}{\pi 12.5^{2}mm^{2}}}=0.17$ mm.

Exothermic Reaction and Energy release

Burn rate, detonation velocity. https://en.wikipedia.org/wiki/Table_of_explosive_detonation_velocities

http://www.explosionsolutions.co.uk/110411016.pdf

https://link.springer.com/article/10.1007/s00193-015-0554-7 $v=1500$ m/s???

Horizontal(?) accelaration due to rapidly expanding air.

Benjamin Robins:

$F(x)={\frac {RPAc}{x}}$

where $x$ distance in barrel, $R$ is the initial ratio of hot gas pressure to atmospheric pressure, $P$ is the atmospheric pressure, $A$ is the cross-sectional area of the ball or bore, $c$ is the length of the barrel occupied by the powder charge before ignition.

$E_{k}=\int _{0}^{L}F(x)dx\iff v_{0}^{2}={\frac {2RP}{m}}{\frac {\pi d^{2}c}{4}}\ln(L/c)$

where Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle d} is the barrel diameter (the bore)

The powder change $p$ is given by $p={\frac {\pi d^{2}c}{4}}\eta$ where $\eta$ is the density of gunpowder.

--

https://www.arc.id.au/RobinsOnBallistics.html

The pressure falls as $1/x$.

--

Bernoulli?

--

$\sum F=0$

$F=ma=pA\iff F=m{\frac {d^{2}x}{dt^{2}}}$

$F=m{\frac {dv}{dt}}=mv{\frac {dv}{dx}}=pA\iff mvdv=pAdx$

$\int mvdv=\int _{0}^{L}pAdx$

where

${\frac {1}{L}}\int _{0}^{L}Pdx=averagepressure={\vec {p}}$

If $A$ is constant

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac12 mv^2 = A \int_0^L p dx = A \vec p L }

then

$v={\sqrt {\frac {2{\vec {p}}AL}{mc_{f}}}}$ and ${\vec {p}}={\frac {c_{f}mv^{2}}{2AL}}$

Projectile friction, rotational energy, heat transfer: correction factor $c_{f}$.

The average pressure is 25% of peak pressure

--

http://closefocusresearch.com/calculating-barrel-pressure-and-projectile-velocity-gun-systems

https://www.arc.id.au/CannonBallistics.html

Maximum Flying Distance

By the conservation of energy, all explosive energy is transferred into the kinetic energy.

$E_{\textrm {explosion}}=E_{\text{kinetic}}$

The distance covered by a projectile with initial velocity $v_0$ is

$s={\frac {v_{0}^{2}}{g}}\sin(2\alpha )={\frac {}{}}$

The drag coefficient $c_{d}$ needs to be found. For the circular disc (a coin) the drag coefficient is almost constant for all velocities (Reynold numbers). The coefficient of drag for a cylinder in this orientation is about 0.81 so long as the length to diameter ratio is greater than 2, see http://www.aerospaceweb.org/question/aerodynamics/q0231.shtml. The cone in either end gives some complications.

The drag equation for the drag force is $F_{D}={\frac {1}{2}}\rho v^{2}c_{d}A$.

Piezo Crystal

To ignite the air--ethanol mixture, we use piezo crystal. When tjhe piezo crystal is compressed, it will generate an electric charge which creates a spark.

References

https://nptel.ac.in/content/storage2/courses/123106002/MODULE%20-%20I/Lecture%201.pdf

https://www.peacesoftware.de/einigewerte/o2_e.html

http://www.users.miamioh.edu/sommerad/NSF%20Files/drag_coefficient_calculation.pdf

DRAG COEFFICIENTS FOR FLAT PLATES , SPHERES, AND CYLINDERS MOVING AT LOW REYNOLDS NUMBERS IN A VISCOUS FLUID by ALVA MERLE JONES

http://www.aerospaceweb.org/question/aerodynamics/q0231.shtml

Ethanol rockets

https://www.youtube.com/watch?v=zTwz6FGobCA Ethanol Rocket - Cool Science Experiment

https://www.youtube.com/watch?v=4s-SZypWxeg Ethanol Explosion - Cool Science Experiment