Diesel Cycle

From wikiluntti

Introduction

Ratio of specific heats (heat capacity ratio) is defined as


  1. Isentropic (adiabatic) expansion
  2. Isochoric cooling (Qout): Heat rejection. Power stroke ends, heat rejection starts.
  3. Isobaric compression: Exhaust
  4. Isobaric expansion: Intake
  5. Isentropic (adiabatic) compression
  6. Isobaric heating (Qin): Combustion of fuel (heat is added in a constant pressure;)

Engine displacement is the cylinder volume swept by all of the pistons of a piston engine, excluding the combustion chambers. A combustion chamber is part of an internal combustion engine in which the fuel/air mix is burned.

Realistic Diesel Cycle

Diesel-air Mixture

The heat capacity ratio (known as the adiabatic index) for a diesel-air mixture is typically around 1.4.

heat capacity ratio Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \gamma</gamma> |- | 14.5:1 || Near-stoichiometric; good combustion efficiency but higher emissions. |- | 16:1 || Balanced performance; good power output and efficiency. |- | 18:1 || Lean burn; improved fuel economy but potential for higher NOx emissions. |} Diesel is a complicated compound, but it’s commonly approximated as a hydrocarbon like C<sub>12</sub>H<sub>23</sub> (or C<sub>12</sub>H<sub>26</sub>). Air is about 21% O<sub>2</sub> and 79% N<sub>2</sub>. Without nitrogen, the stoichiometric ratio is about C<sub>12</sub>​H<sub>23</sub>​+17.75O<sub>2</sub>​→12CO<sub>2</sub>​+11.5H<sub>2</sub>​O and by including nitrogen, we get C<sub>12</sub>​H<sub>23</sub>​+17.75( O<sub>2</sub> + 3.76 N<sub>2</sub> )​→12CO<sub>2</sub>​+11.5H<sub>2</sub>​O + 66.74 N<sub>2</sub>. The molar masses * Fuel: 167 g/mol * Air: 137.28 g/mol And the total air needed is 17.72 x 137.28 = 2436 g, which gives air-to-fuel-ratio to <math> AFR = \frac{2436}{167} = 14.6:1 }

MB data

Mercedes Benz W211 (2003)

  • Engine displacement: 3222 cm3
  • Bore x Stroke: 88.0 x 88.4 mm3
  • Compression Ratio: 18.0

Bore x stroke gives V = 6xπ(8.8/2)2 x 8.84 cm3 = 3225.95cm3, which is rather close.

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