Eksperimentti: hyppykorkeuden määrittäminen impulssilla: Difference between revisions
From wikiluntti
(→Theory) |
(→Theory) |
||
Line 7: | Line 7: | ||
== Theory == | == Theory == | ||
Impulse <math>J = \int F dt = \Delta p = m\Delta v</math>. Actually <math>\Delta v</math> is our takeoff speed because <math>v_1=0</math>, and we have <math>\Delta v = v_{0} = \frac{J}{m} = \frac1m \int F dt</math>. Because <math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math> | Impulse <math>J = \int F dt = \Delta p = m\Delta v</math>. Actually <math>\Delta v</math> is our takeoff speed because <math>v_1=0</math>, and we have <math>\Delta v = v_{0} = \frac{J}{m} = \frac1m \int F dt</math>. Because <math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt</math> and <math>t=\frac{v_0}{g}</math>. Combining these two we have | ||
<math> | <math> | ||
\begin{matrix} | \begin{matrix} | ||
h &= v_0 t - \tfrac12 gt^2 \\ | h &= v_0 t - \tfrac12 gt^2 \\ | ||
&= | &= v_0 \tfrac{v_0}g - \tfrac12 gt^2 \\ | ||
&= | &= s | ||
\end{matrix} | \end{matrix} | ||
</math> | </math> |
Revision as of 17:07, 3 May 2022
Introduction
Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.
Theory
Impulse . Actually is our takeoff speed because , and we have . Because and thus we have because and . However, for the velocity we have and at the maximum height we have that , and thus and . Combining these two we have