Eksperimentti: hyppykorkeuden määrittäminen lentoajalla.: Difference between revisions
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<math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt_m</math> | <math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt_m</math>. Combining these two we have | ||
<math> | <math> |
Revision as of 18:05, 3 May 2022
Introduction

Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.
Theory

and thus we have because and . However, for the velocity we have and at the maximum height we have that , and thus . Combining these two we have
The time at the maximum height () will be half of the flight time.
In the experiment, we have s, which gives m.
Also take-off velocity is easy to calculate as a difference.