Eksperimentti: hyppykorkeuden määrittäminen lentoajalla.: Difference between revisions

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[[File:ForcePlate jumping2 timeOfFlight.svg|thumb]]
[[File:ForcePlate jumping2 timeOfFlight.svg|thumb]]


<math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt_m</math> which. Combining these two we have
<math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt_m</math>. Combining these two we have


<math>
<math>

Revision as of 18:05, 3 May 2022

Introduction

Force exerted on the force plate

Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.

Theory

and thus we have because and . However, for the velocity we have and at the maximum height we have that , and thus . Combining these two we have

The time at the maximum height () will be half of the flight time.

In the experiment, we have s, which gives m.

Also take-off velocity is easy to calculate as a difference.