Eksperimentti: hyppykorkeuden määrittäminen lentoajalla.: Difference between revisions
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<math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = | <math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>. However, for the velocity we have <math>v = v_0 - gt</math> and at the maximum height we have that <math>v=0</math>, and thus <math>v_0 = gt_m</math> which. Combining these two we have | ||
<math> | <math> | ||
\begin{matrix} | \begin{matrix} | ||
h &= v_0 t - \tfrac12 gt^2 \\ | h &= v_0 t - \tfrac12 gt^2 \\ | ||
&= | &= gt_m^2 - \tfrac12 gt_m^2 \\ | ||
\end{matrix} | \end{matrix} | ||
</math> | </math> |
Revision as of 17:43, 3 May 2022
Introduction

Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.
Theory
and thus we have because and . However, for the velocity we have and at the maximum height we have that , and thus which. Combining these two we have
Also take-off velocity is easy to calculate as a difference.