Eksperimentti: hyppykorkeuden määrittäminen lentoajalla.: Difference between revisions

Revision as of 17:34, 3 May 2022

Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.

$s=s_{0}+v_{0}t+{\tfrac {1}{2}}at^{2}$ and thus we have $h=v_{0}t-{\tfrac {1}{2}}gt^{2}$ because $h_{0}=0$ and $a=-g=-9.81m/s^{2}$ .

However, at the maximum height we have that $v=0$ , and thus $v=v_{0}-gt$

$h={\frac {v^{2}}{2g}}$

Also take-off velocity is easy to calculate as a difference.

@@ Line 11: / Line 11: @@
 <math>s = s_0 + v_0 t + \tfrac12 at^2</math> and thus we have <math>h = v_0 t - \tfrac12 gt^2</math> because <math>h_0=0</math> and <math>a=-g = -9.81m/s^2</math>.
+However, at the maximum height we have that <math>v=0</math>, and thus <math>v = v_0 - gt</math>
+<math>h = \frac{v^2}{2g}</math>
 Also take-off velocity is easy to calculate as a difference.