Diesel Cycle: Difference between revisions

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For the constant pressure ('''isobaric process''') <math>\Delta p = 0</math> we have <math>W = \int p dV = p \Delta V</math>, and by applying the ideal gas law, we get <math>W = n R \Delta T</math>.  
For the constant pressure ('''isobaric process''') <math>\Delta p = 0</math> we have <math>W = \int p dV = p \Delta V</math>, and by applying the ideal gas law, we get <math>W = n R \Delta T</math>.  


For the '''Isochoric process''' <math>\Delta V=0</math>, and thus we have <math>dU = dQ</math>.  
For the '''Isochoric process''' <math>\Delta V=0</math>, and thus we have <math>dU = dQ = mc_v dT</math> which gives <math>\Delta Q = m c_v\Delta T</math>.  


<math>
<math>

Revision as of 21:35, 30 March 2026

Introduction

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Ratio of specific heats (heat capacity ratio) is defined as Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \gamma = \frac{ C_p }{ C_v } }

pV diagram

  1. Isentropic (adiabatic) expansion
  2. Isochoric cooling (Qout): Heat rejection. Power stroke ends, heat rejection starts.
  3. Isobaric compression: Exhaust
  4. Isobaric expansion: Intake
  5. Isentropic (adiabatic) compression
  6. Isobaric heating (Qin): Combustion of fuel (heat is added in a constant pressure;)

Engine displacement is the cylinder volume swept by all of the pistons of a piston engine, excluding the combustion chambers. A combustion chamber is part of an internal combustion engine in which the fuel/air mix is burned.

Only air is compressed, and then diesel fuel is injected directly into that hot, high-pressure air.

  • Cylinder pressure: ~30–80 bar
  • Injection pressure: ~1,000–2,500+ bar

Diesel Cycle and Ideal Gas

There are three (3) different processes:

  1. Isentropic Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = nC_v dT = -pdV}
  2. Isobaric Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Q = \Delta U + p \Delta V}
  3. Isochoric Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Delta Q = m c_v \Delta T}

where the specific heat capacity at constant volume is Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c_v = \frac{dQ/dT}{m}} .


For a closed system, the total change in energy of a system is the sum of the work done and the heat added Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = \delta W + \delta Q} , and the reversible work done on a system by changing the volume is Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \delta W = - p dV} . Furthermore, for any transformation of an ideal gas, it is always true that Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = nC_v dT} .


If the system is reversible and adiabatic (isentropic) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \delta Q = 0} , which gives

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = \delta W + \delta Q = -pdV + 0 }


Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = nC_v dT = -pdV }

For the constant pressure (isobaric process) Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Delta p = 0} we have Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle W = \int p dV = p \Delta V} , and by applying the ideal gas law, we get Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle W = n R \Delta T} .

For the Isochoric process Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Delta V=0} , and thus we have Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle dU = dQ = mc_v dT} which gives Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \Delta Q = m c_v\Delta T} .

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle }

Real gas: Air

Basic ideal gas model (good first approximation). Air is usually approximated as an ideal gas with:

  • Gas constant:
    • R≈287 J/(kg\cdotpK)
    • R≈287J/(kg\cdotpK)
  • Equation of state:
  • p=ρRT

This works well at:

  • pressures near atmospheric
  • temperatures roughly 200–500 K


“Generalized” ideal gas → temperature-dependent properties. To go beyond the simple model, you allow properties like heat capacity to vary with temperature:

Heat capacity. For air, a common approximation is a polynomial Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c_p(T)=a+bT. } Typical coefficients (for dry air, ~200–1000 K range):

  • a≈1005
  • b≈0.1

More accurate forms come from NASA polynomials: Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \frac{c_p}R=a_1+a_2T+a_3T^2+a_4T^3+a_5T^4 } Which are widely used in CFD and thermodynamics.

Compressibility factor Z (real gas correction). If you want a generalized ideal gas, you often introduce Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle p=Z\rho RT} . Where

  • Z=1 → ideal gas
  • Z≠1 → real gas behavior

For air:

  • At normal conditions: Z≈1
  • At high pressure: use virial expansion

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle Z=1+\frac{B(T)}V+\frac{C(T)}{V^2}+ \cdots \approx 1+ \frac{B(T)}{RT}p. }


Mixture-based formulation (more fundamental). Air is a mixture mainly of:

  • N₂ (~78%)
  • O₂ (~21%)
  • Ar (~1%)

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} R &=\sum_i y_i R_i \\ c_p & = \sum_i y_ i c_{p,i}(T) \end{align} }

Realistic Diesel Cycle

Ratio of specific heats γ

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \gamma = \frac{ \sum y_1 c_{p,i} }{ \sum y_1 ( c_{p,i} -R_u ) } }

Caption text
Condition γ (approx.)
Stoichiometric ~1.30–1.33
Moderate lean ~1.33–1.37
Very lean (diesel) ~1.37–1.40

Injection pressures

  • Older systems: 200–500 bar
  • Modern common-rail: 1,000–2,500 bar
  • Latest systems: up to ~3,000 bar
  • Air pressure in cylinder: ~30–80 bar, which is the pressure of the combustion chamber.
  • Temperature: ~700–1000 K

Diesel-air Mixture

Only diesel is ejected into the cylinder. Clean air comes in during the intake stroke.

The heat capacity ratio (known as the adiabatic index) for a diesel-air mixture is typically around 1.4.

Air-fuel ratio
14.5:1 Near-stoichiometric; good combustion efficiency but higher emissions.
16:1 Balanced performance; good power output and efficiency.
18:1 Lean burn; improved fuel economy but potential for higher NOx emissions.


Diesel is a complicated compound, but it’s commonly approximated as a hydrocarbon like C12H23 (or C12H26). Air is about 21% O2 and 79% N2. Without nitrogen, the stoichiometric ratio is about

C12​H23​+17.75O2​→12CO2​+11.5H2​O

and by including nitrogen, we get

C12​H23​+17.75( O2 + 3.76 N2 )​→12CO2​+11.5H2​O + 66.74 N2.

The molar masses

  • Fuel: 167 g/mol
  • Air: 137.28 g/mol

And the total air needed is 17.72 x 137.28 = 2436 g, which gives air-to-fuel-ratio to

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle AFR = \frac{2436}{167} = 14.6:1 }

MB data

Motor: OM648.

Mercedes Benz W211 (2003)

  • Engine displacement: 3222 cm3 = 0.003222 m3
  • Bore x Stroke: 88.0 x 88.4 mm3
  • Compression Ratio: 18.0

Bore x stroke gives V = 6xπ(8.8/2)2 x 8.84 cm3 = 3225.95cm3, which is rather close.

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle p_1 V_1^\gamma = \text{constant}_1 }

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