Integer division that rounds up: Difference between revisions
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because <math>0 \leq \frac{y-1}y < 1</math>. This is ok. | because <math>0 \leq \frac{y-1}y < 1</math>. This part is ok. | ||
'''Part 2'''. If <math>y</math> does not divide <math>x</math> we have <math>x=by + r</math> for some <math>b\in\mathbb N_+</math> and <math>0<r<b-1</math>. Thus we have | |||
Revision as of 10:10, 8 July 2024
Introduction
Usual integer division rounds down: for . To round up (if overflow is not an issue), you can use following algorithm with the usual roundig down division:
Proof
Proof is in two parts; 1st if divides , and if not. Note that usual integer division rounds down.
Part 1. If divides we have Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=ay} for some Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a\in\mathbb N_+} . Thus we have
Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} \left \lceil \frac{x+y-1}{y} \right \rceil &= \left \lceil \frac{x}{y} + \frac{y-1}y \right \rceil \\ &= \left \lceil \frac{ay}{y} + \frac{y-1}y \right \rceil \\ &= \frac{ay}{y} \\ &= \frac{x}{y} \end{align} }
because Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0 \leq \frac{y-1}y < 1} . This part is ok.
Part 2. If Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y} does not divide Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x} we have Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x=by + r} for some Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b\in\mathbb N_+} and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle 0<r<b-1} . Thus we have