Brachistochrone: Difference between revisions

From wikiluntti
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t = \int_{P_a}^{P_b} \frac 1 v ds
t = \int_{P_a}^{P_b} \frac 1 v ds
</math>
</math>
where <math>ds= \sqrt{1+y'^2}dx</math> is the Pythagorean distance measure and <math>v</math> is determined from the the law of conservation of energy
where <math>ds= \sqrt{1+y'{^2}}dx</math> is the Pythagorean distance measure and <math>v</math> is determined from the the law of conservation of energy
<math>
<math>
\frac12 mv^2 = mgy  
\frac12 mv^2 = mgy  

Revision as of 18:30, 16 February 2021

Introduction

To find the shape of the curve which the time is shortest possible. . .

Theory

The time from to is where is the Pythagorean distance measure and is determined from the the law of conservation of energy . giving . Plugging these in, we get , where is the function subject to variational consideration.

According to the Euler--Lagrange differential equation the stationary value is to be found, if E-L equation is satisfied.

No Friction

We get


Because ,

Friction

Rolling Ball

References

https://mathworld.wolfram.com/BrachistochroneProblem.html

https://physicscourses.colorado.edu/phys3210/phys3210_sp20/lecture/lec04-lagrangian-mechanics/