Eksperimentti: hyppykorkeuden määrittäminen lentoajalla.: Difference between revisions

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In the experiment, we have <math>t_m = 0.16</math> s, which gives <math> h = \tfrac12 gt_m^2 = \frac12 \times 9.81 \times 0.16^2 = 0.13</math> m.  
In the experiment, we have <math>t_m = 0.16</math> s, which gives <math> h = \tfrac12 gt_m^2 = \frac12 \times 9.81 \times 0.16^2 = 0.13</math> m.  


Also take-off velocity is easy to calculate as a difference.
The takeoff velocity is <math>v_0 = gt_m = 9.81 m/s^2 \times 0.16 s =  1.5696 m/s</math>.

Latest revision as of 19:12, 3 May 2022

Introduction

Force exerted on the force plate

Jumping on the force plate you can feel the force. We use time of flight method to estimate the height of the jump.

Theory

and thus we have because and . However, for the velocity we have and at the maximum height we have that , and thus . Combining these two we have

The time at the maximum height () will be half of the flight time.

Example

In the experiment, we have Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t_m = 0.16} s, which gives Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle h = \tfrac12 gt_m^2 = \frac12 \times 9.81 \times 0.16^2 = 0.13} m.

The takeoff velocity is Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle v_0 = gt_m = 9.81 m/s^2 \times 0.16 s = 1.5696 m/s} .